6cos^2(2x)-5cos(2x)+7=0

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Solution for 6cos^2(2x)-5cos(2x)+7=0 equation:


Simplifying
6cos2(2x) + -5cos(2x) + 7 = 0

Remove parenthesis around (2x)
6cos2 * 2x + -5cos(2x) + 7 = 0

Reorder the terms for easier multiplication:
6 * 2cos2 * x + -5cos(2x) + 7 = 0

Multiply 6 * 2
12cos2 * x + -5cos(2x) + 7 = 0

Multiply cos2 * x
12cos2x + -5cos(2x) + 7 = 0

Remove parenthesis around (2x)
12cos2x + -5cos * 2x + 7 = 0

Reorder the terms for easier multiplication:
12cos2x + -5 * 2cos * x + 7 = 0

Multiply -5 * 2
12cos2x + -10cos * x + 7 = 0

Multiply cos * x
12cos2x + -10cosx + 7 = 0

Reorder the terms:
7 + -10cosx + 12cos2x = 0

Solving
7 + -10cosx + 12cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -10cosx + -7 + 12cos2x = 0 + -7

Reorder the terms:
7 + -7 + -10cosx + 12cos2x = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -10cosx + 12cos2x = 0 + -7
-10cosx + 12cos2x = 0 + -7

Combine like terms: 0 + -7 = -7
-10cosx + 12cos2x = -7

Reorder the terms:
7 + -10cosx + 12cos2x = -7 + 7

Combine like terms: -7 + 7 = 0
7 + -10cosx + 12cos2x = 0

The solution to this equation could not be determined.

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